0=-1.5x^2+36x+6

Solution for 0=-1.5x^2+36x+6 equation:

0=-1.5x^2+36x+6

We move all terms to the left:

0-(-1.5x^2+36x+6)=0

We add all the numbers together, and all the variables

-(-1.5x^2+36x+6)=0

We get rid of parentheses

1.5x^2-36x-6=0

a = 1.5; b = -36; c = -6;
Δ = b2-4ac
Δ = -362-4·1.5·(-6)
Δ = 1332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1332}=\sqrt{36*37}=\sqrt{36}*\sqrt{37}=6\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{37}}{2*1.5}=\frac{36-6\sqrt{37}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{37}}{2*1.5}=\frac{36+6\sqrt{37}}{3}
$